Question

In: Chemistry

A student ran the following reaction in the laboratory at 291 K: 2CH2Cl2(g) CH4(g) + CCl4(g)...

A student ran the following reaction in the laboratory at 291 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When she introduced 6.63×10-2 moles of CH2Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of CH2Cl2(g) to be 4.92×10-3 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.

Kc = _____

Solutions

Expert Solution


Related Solutions

A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) +...
A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) + Cl2(g) When she introduced 1.28 moles of PCl5(g) into a 1.00 liter container, she found the equilibrium concentration of PCl5(g) to be 1.24 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) +...
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.47×10-2 M CH2Cl2, 0.177 M CH4 and 0.177 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.44×10-2 mol of CH2Cl2(g) is added to the flask? [CH2Cl2] =_____ M [CH4] = ________M [CCl4] =________ M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) =CH4(g) +...
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) =CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.12×10-2 M CH2Cl2, 0.166 M CH4 and 0.166 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.121 mol of CH4(g) is added to the flask? [CH2Cl2] = _________M [CH4] = _________ M [CCl4] = _________ M
1. A student ran the following reaction in the laboratory at 582 K: CO(g) + Cl2(g)...
1. A student ran the following reaction in the laboratory at 582 K: CO(g) + Cl2(g)      COCl2(g) When she introduced 0.380 moles of CO(g) and 0.403 moles of Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of COCl2(g) to be 0.342 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. 2. The equilibrium constant, Kc, for the following reaction is 1.29×10-3 at 540 K. COCl2(g) CO(g) + Cl2(g) When a sufficiently large sample of COCl2(g)...
A student ran the following reaction in the laboratory at 684 K: N2(g) + 3H2(g) 2NH3(g)...
A student ran the following reaction in the laboratory at 684 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.26×10-2 moles of N2(g) and 6.07×10-2 moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of H2(g) to be 5.83×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = __
-A student ran the following reaction in the laboratory at 1143 K: 2SO2(g) + O2(g) 2SO3(g)...
-A student ran the following reaction in the laboratory at 1143 K: 2SO2(g) + O2(g) 2SO3(g) When she introduced 8.19×10-2 moles of SO2(g) and 8.56×10-2 moles of O2(g) into a 1.00 liter container, she found the equilibrium concentration of O2(g) to be 6.08×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =____________ -A student ran the following reaction in the laboratory at 363 K: CH4(g) + CCl4(g)      2CH2Cl2(g) When she introduced 4.64×10-2 moles of CH4(g) and...
A student ran the following reaction in the laboratory at 720 K: H2(g) + I2(g) 2HI(g)...
A student ran the following reaction in the laboratory at 720 K: H2(g) + I2(g) 2HI(g) When she introduced 0.189 moles of H2(g) and 0.218 moles of I2(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 6.05×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 610 K: CO(g) + Cl2(g) COCl2(g)...
A student ran the following reaction in the laboratory at 610 K: CO(g) + Cl2(g) COCl2(g) When she introduced 0.183 moles of CO(g) and 0.211 moles of Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 6.72×10-2 M.   Calculate the equilibrium constant, Kc, she obtained for this reaction. 2.A student ran the following reaction in the laboratory at 546 K: COCl2(g) CO(g) + Cl2(g)   When she introduced 0.854 moles of COCl2(g) into a 1.00...
The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) ------CH4(g) +...
The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) ------CH4(g) + CCl4(g) Calculate the equilibrium concentrations of reactant and products when 0.321 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350 K. [CH2Cl2] = ------------M [CH4] = ------- M [CCl4] = ------ M
The equilibrium constant, Kc, for the following reaction is 33.3 at 297 K. 2CH2Cl2(g) <-------->>>CH4(g) +...
The equilibrium constant, Kc, for the following reaction is 33.3 at 297 K. 2CH2Cl2(g) <-------->>>CH4(g) + CCl4(g) When a sufficiently large sample of CH2Cl2(g) is introduced into an evacuated vessel at 297 K, the equilibrium concentration of CCl4(g) is found to be 0.322 M. Calculate the concentration of CH2Cl2 in the equilibrium mixture.  M
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT