The equilibrium constant, Kc, for the following reaction is 33.3 at 297 K. 2CH2Cl2(g) <-------->>>CH4(g) +...

The equilibrium constant, K_c, for the following reaction is 33.3 at 297 K.

2CH₂Cl₂(g) <-------->>>CH₄(g) + CCl₄(g)

When a sufficiently large sample of CH₂Cl₂(g) is introduced into an evacuated vessel at 297 K, the equilibrium concentration of CCl₄(g) is found to be 0.322 M.

Calculate the concentration of CH₂Cl₂ in the equilibrium mixture. M

Expert Solution

2CH₂Cl₂(g) <-------->>>CH₄(g) + CCl₄(g)

I x 0 0

C -0.322 0.322 0.322

E x-0.322 0.322 0.322

Kc = [CH4][CCl4]/[CH2Cl2]²

33.3 = 0.322*0.322/(x-0.322)^2

33.3(x-0.322)^2 = 0.322*0.322

x = 0.377

[CH2Cl2] = x-0.322

= 0.377-0.322 = 0.055M >>>>answer

queen_honey_blossom answered 2 years ago

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