Question

In: Computer Science

a) In a subnet, a host has been assigned the following configuration parameters: 10.42.4.232/13. What is the...

a) In a subnet, a host has been assigned the following configuration parameters: 10.42.4.232/13. What is the last valid IP address on the network that this host is a part of?

b) In a subnet, a host has been assigned the following configuration parameters: 172.20.122.6/255.255.248.0. What is the broadcast address on the network that this host is a part of?

c) In a subnet, a host has been assigned the following configuration parameters: 10.158.253.161/255.192.0.0. What is the broadcast address on the network that this host is a part of?

d) In a subnet, a host has been assigned the following configuration parameters: 192.168.27.76/28. What is the first valid IP address on the network that this host is a part of?

e) In a subnet, a host has been assigned the following configuration parameters: 10.26.22.90/12. What is the first valid IP address on the network that this host is a part of?

All answers must be in dotted decimal notation.

Expert Solution

a.

The IP address given is: 10.42.4.232/13

Host bits = 32 - 13 = 19

Number of hosts , = 524288

Number of valid hosts = 524288 - 2 = 524286

Broadcast address is: Wild Card Mask (00000000.00000111.11111111.11111111) OR Network Address (00001010.00101010.00000100.11101000)

00000000.00000111.11111111.11111111

+ 00001010.00101010.00000100.11101000

00001010. 00101111.11111111.11111111

i.e., 10.47.255.255 is the broadcast address.

So, the last valid IP address is: 10.47.255.254

b.

The IP address given is: 172.20.122.6/255.255.248.0

Mask is: /21

Host bits = 32 - 21 = 9

Number of hosts , = 512

Number of valid hosts = 512 - 2 = 510

Broadcast address is: Wild Card Mask (00000000.00000000.00000111.11111111) OR Network Address (10101100.00010100.01111010.00000110)

00000000.00000000.00000111.11111111

+ 10101100.00010100.01111010.00000110

10101100.00010100.01111111.11111111

i.e., Broadcast address: 172.20.127.255

c.

Given, IP address is: 10.158.253.161/255.192.0.0

Mask is: /10

Host bits = 32 -10 = 22

Number of hosts , = 4194304

Number of valid hosts = 4194304 - 2 = 4194302

Broadcast address is: Wild Card Mask (00000000.00111111.11111111.11111111) OR Network Address (00001010.10011110.11111101.10100001)

00000000.00111111.11111111.11111111

+00001010.10011110.11111101.10100001

00001010.10111111.11111111.11111111

Broadcast address is: 10.191.255.255

d.

Given, IP address is: 192.168.27.76/28

Host bits = 32 - 28 = 4

Number of hosts = = 16

Number of valid hosts = 16 - 2 = 14

The first valid IP address is: 192.168.27.64

e.

Given, IP address is: 10.26.22.90/12

Host bits: 32 - 12 = 20

Number of hosts: = 1048576

Number of valid hosts: 1048576 - 2 = 1048574

The first valid IP address is: 10.26.0.1

venereology answered 1 day ago

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