A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) +...

A student ran the following reaction in the laboratory at 445 K

: PCl5(g)-------> PCl3(g) + Cl2(g)

When she introduced 1.28 moles of PCl5(g) into a 1.00 liter container, she found the equilibrium concentration of PCl5(g) to be 1.24 M.

Calculate the equilibrium constant, Kc, she obtained for this reaction.

Expert Solution

molarity of PCl5 = no of moles/volume in L

= 1.28/1 = 1.28M

PCl5(g)-------> PCl3(g) + Cl2(g)

I 1.28 0 0

C -0.04 0.04 0.04

E 1.24 0.04 0.04

[PCl5] = 1.24M

[PCl3] = 0.04M

[Cl2] = 0.04M

Kc = [PCl3][Cl2]/[PCl5]

= 0.04*0.04/1.24 = 0.0013 = 1.3*10^-3 >>>>>answer

queen_honey_blossom answered 2 years ago

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