Question

In: Chemistry

What was the initial concentration of 100ml of KBr solution, if after adding water to dilute...

What was the initial concentration of 100ml of KBr solution, if after adding water to dilute it, 300ml of a 4 percent solution was obtained?

Solutions

Expert Solution

Ans. Given, 300 mL of a 4% solution was obtained after dilution. It’s assumed that the given concentration is in terms of %(w/v), where, w= weight of solute (i.e. KBr) in 100 mL solution.

4% w/v solution means 4 gram KBr in 100 mL solution

Since, 100 mL solution contain 4 gram KBr

            Or, 1 mL            -           -    (4/ 100) gm KBr

            Or, 300 mL        -           -    (4/ 100) x 100 = 12 gram KBr.

Now, since only distilled water was added during dilution, the net weight (mass) of KBr in the solution remains the same in both the solutions (before and after dilution).

Thus, the amount of KBr in 100 mL (original) solution = 12 gram

Initial concentration (% w/v) = 12 gm KBr in 100 mL solution = 12 % w/v  


Related Solutions

What is the concentration of hydronium ions after a 100mL solution of 0.02M Magnesium Hydroxide and...
What is the concentration of hydronium ions after a 100mL solution of 0.02M Magnesium Hydroxide and 100mL of 0.05M nitric acid?
If the initial concentration of A is 0.00230 M, what will be the concentration after 485...
If the initial concentration of A is 0.00230 M, what will be the concentration after 485 s? How do you know in general what type of order reactions is it (zero, first, second) when it comes to word problems?? also, can I get step by step on how to solve?
what is the concentration of Sucrose solution prepared by adding 200mL to 500mL of a 4.50...
what is the concentration of Sucrose solution prepared by adding 200mL to 500mL of a 4.50 M Sucrose solution?
Having trouble calculating the error of a diluted solution in a 100mL volumetric flask. Concentration is...
Having trouble calculating the error of a diluted solution in a 100mL volumetric flask. Concentration is 0.005 +/- 0.005M Amount of Concentrated solution: 5.0mL +/- 0.1mL Volumetric flask: 100mL +/- 0.08mL My calculation so far is ((0.1/5)+(0.005/0.005)+(0.08/100))*.00025 I keep getting 0.0002552 as my error but the answer key is 0.00003. Whats wrong in my formula?
500mL of a dilute phosphoric acid solution was prepared. If the concentration dropped from 36% to...
500mL of a dilute phosphoric acid solution was prepared. If the concentration dropped from 36% to 2%, how much water was needed for the dilution?
14. A solution is prepared by dissolving 49.3g of KBr in enough water to form 473mL...
14. A solution is prepared by dissolving 49.3g of KBr in enough water to form 473mL of solution. Calculate the mass percent of KBr in the solution if thedensity is 1.12 g/mL. a. 10.4% b. 8.57% c. 10.1% d. 11.7% e. 9.31%
Which one of these salts will form a basic solution upon dissolving in water? A) KBr...
Which one of these salts will form a basic solution upon dissolving in water? A) KBr B) KClO3 C) LiCl D) NaNO3 E) NH4NO3 Please explain how you got the answer for my own reference, I really appreciate it.
a solution if phosphoric acid was made by dissolving 10g of H3PO4 in 100mL of water....
a solution if phosphoric acid was made by dissolving 10g of H3PO4 in 100mL of water. the resulting volume was 104mL. calculate the density, mole fraction, molarity, and molality of the solution. assume water has a density of 1g/cm3
Given the following solubilities in grams/100ml of water (these are the amounts that stay in solution...
Given the following solubilities in grams/100ml of water (these are the amounts that stay in solution at these temperatures): caffeine 1.35g (16 degrees Celcius) 45.5g (65 degrees celcius) NaCl 35.7g (0 degree celcius) 39.1g (100 degrees celcius) Suppose that 20g of a mixture that is 75% caffeine and 25% NaCl is crystallized from 100mL of boiling water and cooled to 16 degrees celcius. a) how much of the caffeine from this mixture stays in solution at 16 degrees celcius? b)...
Outline of procedure: Dilute bleach solution A 1/10. Prepare analyte for titration by adding 10mL of...
Outline of procedure: Dilute bleach solution A 1/10. Prepare analyte for titration by adding 10mL of diluted bleach solution, indicator and 5mL of 2 M HCl. Titrate the analyte with 0.05524 M Na2S2O3. Average volume of Na2S2O3 added = 31.25 mL Question: Calculate the percent of sodium hypochlorite in the original bleach bottle using your averaged result. Show the calculation for solution A only. Which bleach solution is the more potent cleaning agent?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT