Question

what is the concentration of Sucrose solution prepared by adding 200mL to 500mL of a 4.50 M Sucrose solution?

Answer 1

We will calculate the concentration using equation,

M1 V1 = M2 V2

Here, M1 = Initial molarity = 4.50 M

M2 = Final molarity = to be determined

V1 = Initial volume = 200 mL

V2 = Final volume = 500 mL

Putting this values in above equation we get,

4.50 M x 200 mL = M2 x 500 mL

900 M = M2 x 500 mL

Therefore,

M2 = 900 / 500

= 1.8 M

Therefore molarity of sucrose solution is 1.8 M