In: Statistics and Probability
Find a value with a graph, z0, such as:
a) P(z ≥ z0) = 0.06
b) P (z > z0) = 0.85
c) P (-z0 < z < z0) = 0.88
Solution:
Given that,
Using standard normal table,
a) P(z z0) = 0.06
P(z z0) = 1 - 0.06
P(z z0) = 0.94
z0 = 1.55
b) P(z z0) = 0.85
P(z z0) = 1 - 0.85
P(z z0) = 0.15
z0 = -1.04
c) P (-z0 < z < z0) = 0.88
P(Z < z0) - P(Z < z0) = 0.88
2P(Z < z0) - 1 =0.88
2P(Z < z0) = 1 + 0.88
2P(Z < z0) = 1.88
P(Z < z0) = 1.88 / 2 = 0.94
P(Z < z0) = 0.94
z0 = 1.55