(a) Find P [Z > 1.26]. (b) Find P [Z > -1.37}. (c) find P[-1.25 (a)...

(a) Find P [Z > 1.26]. (b) Find P [Z > -1.37}. (c) find P[-1.25

(a) Find P [Z > 1.26]. (b) Find P [Z > -1.37}. (c) find P[-1.25<Z<0.37). (d) find z such that P[Z>z]=0.05. (e) find z such that P[-z<Z<z]=0.99. (f) find the value of k such that P[k<Z<-0.18]=0.4197

Expert Solution

orchestra answered 2 years ago

P(z ≥ −1.26) P(−1.23 ≤ z ≤ 2.64) P(−2.18 ≤ z ≤ 0.96) P(−0.83 ≤ z...

P(z ≥ −1.26) P(−1.23 ≤ z ≤ 2.64) P(−2.18 ≤ z ≤ 0.96) P(−0.83 ≤ z ≤ 0)

For a standard normal distribution, find 1. P(z > c)=0.3796 Find c. 2. P(z < c)=0.0257...

For a standard normal distribution, find 1. P(z > c)=0.3796 Find c. 2. P(z < c)=0.0257 Find c. 3. P(-2.68< z > -0.38) 4. P(z > -1.55) 5. P(z < -0.32)

Find the following probabilities for the standard normal random variable z: (a) P(−0.76<z<0.75)= (b) P(−0.98<z<1.36)= (c)...

Find the following probabilities for the standard normal random variable z: (a) P(−0.76<z<0.75)= (b) P(−0.98<z<1.36)= (c) P(z<1.94)= (d) P(z>−1.2)= 2. Suppose the scores of students on an exam are Normally distributed with a mean of 480 and a standard deviation of 59. Then approximately 99.7% of the exam scores lie between the numbers ---- and -----. ?? Hint: You do not need to use table E for this problem.

) Find the following probabilities for the standard normal random variable zz: (a) P(−2≤z≤2.01)= (b) P(−0.5≤z≤1.62)= (c) P(z≤1.3)= (d) P(z>−1.1)=

1. If Z is a standard normal random variable, find c such that P(−c ≤ Z...

1. If Z is a standard normal random variable, find c such that P(−c ≤ Z ≤ c) = 0.82. [Answer to 2 decimal places] 2. Weakly earnings on a certain import venture are approximately normally distributed with a known mean of $353 and unknown standard deviation. If the proportion of earnings over $386 is 25%, find the standard deviation. Answer only up to two digits after decimal. 3. X is a normal random variable with mean μ and standard...

1.- Find the following probabilities. (a) P(Z > 1.4) (b) P(−1 < Z < 1)...

1.- Find the following probabilities. (a) P(Z > 1.4) (b) P(−1 < Z < 1) (c) P(Z < −1.49) 2.- Find (a) Z0.03 (b) Z0.07 3.- The distance that a Tesla model 3 can travel is normally distributed with a mean of 260 miles and a standard deviation of 25 miles. (a) What is the probability that a randomly selected Tesla model 3 can travel more than 310 miles? (b) What is the probability that a randomly selected Tesla...

For the standard normal distribution, find the value of c such that: P(z > c) =...

For the standard normal distribution, find the value of c such that: P(z > c) = 0.0025

Find the value of the standard normal random variable z, called z0 such that: (b) P(−z0≤z≤z0)=0.3264 (c) P(−z0≤z≤z0)=0.8332...

Find the value of the standard normal random variable z, called z0 such that: (b) P(−z0≤z≤z0)=0.3264 (c) P(−z0≤z≤z0)=0.8332 (d) P(z≥z0)=0.3586 (e) P(−z0≤z≤0)=0.4419 (f) P(−1.15≤z≤z0)=0.5152

Find the indicated probabilities using a standard normal distribution a. P(Z < 1.85) b. P(Z <...

Find the indicated probabilities using a standard normal distribution a. P(Z < 1.85) b. P(Z < -1.54 or Z > 1.54)

P( z > -1.26) = ? Question 7 options: 0.8962 0.8229 0.1038 None of the Above

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