If Z is a standard normal random variable, find the
value z0 for the following probabilities. (Round your
answers to two decimal places.)
(a) P(Z > z0) = 0.5
z0 =
(b) P(Z < z0) = 0.9279
z0 =
(c) P(−z0 < Z < z0) = 0.90
z0 =
(d) P(−z0 < Z < z0) = 0.99
z0 =
Find the value of the standard normal random variable z , called
z 0 such that:
a) ?(?≤?0)=0.8998
?0=
(b) ?(−?0≤?≤?0)=0.676
?0=
(c) ?(−?0≤?≤?0)=0.198
?0=
(d) ?(?≥?0)=0.1895
?0=
(e) ?(−?0≤?≤0)=0.4425
?0=
(f) ?(−1.11≤?≤?0)=0.8515
?0=
1. If Z is a standard normal random variable, find
c such that P(−c ≤ Z ≤
c) = 0.82. [Answer to 2 decimal places]
2. Weakly earnings on a certain import venture are approximately
normally distributed with a known mean of $353 and unknown standard
deviation. If the proportion of earnings over $386 is 25%, find the
standard deviation. Answer only up to two digits after decimal.
3. X is a normal random variable with mean μ and
standard...
Find the value of the standard normal random variable z, called
z subscript 0, such that: P left parenthesis z greater or equal
than z subscript 0 right parenthesis equals.20 Find the value of
the standard normal random variable z , called z subscript 0 , such
that Find the value of the standard normal random variable z ,
called z subscript 0 , such that Find the value of the standard
normal random variable z , called z subscript...
Find the value of the standard normal random variable z, called
z subscript 0, such that: P left parenthesis z greater or equal
than z subscript 0 right parenthesis equals.20 Find the value of
the standard normal random variable z , called z subscript 0 , such
that Find the value of the standard normal random variable z ,
called z subscript 0 , such that Find the value of the standard
normal random variable z , called z subscript...
Find the value of the standard normal random variable z, called
z subscript 0, such that: P left parenthesis z greater or equal
than z subscript 0 right parenthesis equals.20 Find the value of
the standard normal random variable z , called z subscript 0 , such
that Find the value of the standard normal random variable z ,
called z subscript 0 , such that Find the value of the standard
normal random variable z , called z subscript...
Find the following probabilities for the standard normal random
variable z:
(a) P(−0.76<z<0.75)=
(b) P(−0.98<z<1.36)=
(c) P(z<1.94)=
(d) P(z>−1.2)=
2.
Suppose the scores of
students on an exam are Normally distributed with a mean of 480 and
a standard deviation of 59. Then approximately 99.7% of the exam
scores lie between the numbers ---- and
-----. ??
Hint: You do not need to use table E for this problem.
Let z be a random variable with a standard normal
distribution.
Find “a” such that P(|Z| <A)= 0.95
This is what I have:
P(-A<Z<A) = 0.95
-A = -1.96
How do I use the symmetric property of normal distribution to make
A = 1.96?
My answer at the moment is P(|z|< (-1.96) = 0.95
1. For a standard normal distribution, determine the z-score,
z0, such that P(z < z0) = 0.9698.
2. From a normal distribution with μμ = 76 and σσ = 5.9, samples
of size 46 are chosen to create a sampling distribution. In the
sampling distribution determine P(74.399 < ¯xx¯ <
78.079).
3. From a normal distribution with μμ = 81 and σσ = 2.7, samples
of size 48 are chosen to create a sampling distribution. In the
sampling distribution determine...