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In Cats, Short Hair (H) is dominant to , Long hair (h). Tabby (T) is dominant...

In Cats, Short Hair (H) is dominant to , Long hair (h). Tabby (T) is dominant to , Stripless (t). Normal, no colorpoint (N) is dominant to, Colorpoint (n).

I. A homozygous short hair, homozygous stripeless cat and a homozygous long hair, homozygous tabby cat have kittens.

a. Draw the Punnett Square (4x4 square).

b. What is the phenotype ratio?____________________________

c. What percentage of the offspring will have short hair and be stripeless? _____________

II. A heterozygous tabby, heterozygous normal cat and a homozygous stripeless, homozygous colorpoint cat have kittens.

a. Draw the Punnett Square (4x4 square).

b. What is the phenotype ratio?____________________________

c. What percentage of the offspring will be tabby and colorpoint? _____________

d. What percentage of the offspring will have stripeless and normal? _______________

III. A solid colored, short-haired female rabbit (ssHH) is mated to a spotted, long-haired male rabbit (SShh).

a. Draw the Punnett Square.

How many out of 16 will be expected to be spotted with long hair? ________________________

How many out of 16 will be expected to be spotted with short hair? ________________________

Solutions

Expert Solution

a. HHtt x hhTT

Gametes from HHtt : Ht, Ht, Ht, Ht

Gametes from hhTT : hT, hT, hT, hT

Punnett Square Analysis:

	Ht	Ht	Ht	Ht
hT	HhTt	HhTt	HhTt	HhTt
hT	HhTt	HhTt	HhTt	HhTt
hT	HhTt	HhTt	HhTt	HhTt
hT	HhTt	HhTt	HhTt	HhTt

b. The Punnett square analysis shows that all kittens will have short hair and be tabby.

So the phenotypic ratio is: 4:0

c. 0% of the offspring will have short hair and be stripeless.

II.

TtNn x ttnn

Gametes from TtNn : TN, Tn, tN, tn

Gametes from ttnn : tn, tn, tn, tn

Punnett square analysis:

	TN	Tn	tN	tn
tn	TtNn (Tabby and normal)	Ttnn (Tabby and colorpoint)	ttNn (Stripless and normal)	ttnn (Stripless and colorpoint)
tn	TtNn (Tabby and normal)	Ttnn (Tabby and colorpoint)	ttNn (Stripless and normal)	ttnn (Stripless and colorpoint)
tn	TtNn (Tabby and normal)	Ttnn (Tabby and colorpoint)	ttNn (Stripless and normal)	ttnn (Stripless and colorpoint)
tn	TtNn (Tabby and normal)	Ttnn (Tabby and colorpoint)	ttNn (Stripless and normal)	ttnn (Stripless and colorpoint)

b. The phenotypic ratio is 1:1:1:1

c. 25% of the offspring will be tabby and colorpoint.

d. 25% of the offspring will have stripeless and normal.

III.

ssHH x SShh

Gametes from ssHH: sH, sH, sH, sH

Gametes from SShh: Sh, Sh, Sh, Sh

	sH	sH	sH	sH
Sh	SsHh	SsHh	SsHh	SsHh
Sh	SsHh	SsHh	SsHh	SsHh
Sh	SsHh	SsHh	SsHh	SsHh
Sh	SsHh	SsHh	SsHh	SsHh

The above Punnett square analysis shows that all offspring will be spotted and will have short hair.

Out of 16, no offspring are expected to be spotted with long hair.

All 16 offspring are expected to be spotted with short hair.

gladiator answered 1 year ago

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