Question

In: Biology

In peas, tall (T) is dominant to short (t), yellow (Y) is dominant to green (y)...

In peas, tall (T) is dominant to short (t), yellow (Y) is dominant to green (y) and round (R) is dominant to wrinkled (r). A purebreeding plant with tall, green and wrinkled pea phenotypes is crossed to a purebreeding plant that is short and makes yellow, round peas. When peas from this F1 generation are crossed, what is the probability of obtaining a short plant that makes yellow, wrinkled peas in the F2?

Solutions

Expert Solution

Pure breeding plant is one that is homozygous for the allele.

Genotype of a purebreeding plant with tall, green and wrinkled pea phenotypes is

TTyyrr

Genotype of a purebreeding plant with short and makes yellow, round peas phenotypes is

ttYYRR

F1 cross of a TTyyrr X ttYYRR cross will give TtYyRr offspring.

Since it’s a trihybrid cross (TtYyRr X TtYyRr) is difficult to show in a Punnet square (64 boxes), we use th forked-line method to calculate the probability

Each monohybrid cross give 3: 1 phenotypic ratio

The genetic probabilities are determined by multiplying together the probabilities of each phenotype.

Tall/Dwarf                   Round or Wrinkled Yellow or green Observed product Phenotype

¾ tall                              ¾ round ¾ yellow (3/4) * (3/4)*(3/4) 27/64 tall, round, yellow

¼ green (3/4) * (3/4)*(1/4) 9/64 tall, round, green

                                        ¼ Wrinkled ¾ yellow (3/4) * (1/4)*(3/4) 9/64 tall, wrinkled, yellow

¼ green (3/4) * (1/4)*(1/4) 3/64 tall, wrinkled , green

¾ short ¾ round ¾ yellow (1/4) * (3/4)*(3/4) 9/64 short, round, yellow

¼ green (1/4) * (3/4)*(1/4) 3/64 short, round, green

                                        ¼ Wrinkled             ¾ yellow (1/4)*(1/4)*(3/4) 3/64 short, wrinkled, yellow

¼ green (1/4) * (1/4)*(1/4) 1/64 short, wrinkled, green

Probability of obtaining short plant that makes yellow, wrinkled peas in the F2 (short, wrinkled green) is 3/64.

  


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