In: Biology
In peas, tall (T) is dominant to short (t), yellow (Y) is dominant to green (y) and round (R) is dominant to wrinkled (r). A purebreeding plant with tall, green and wrinkled pea phenotypes is crossed to a purebreeding plant that is short and makes yellow, round peas. When peas from this F1 generation are crossed, what is the probability of obtaining a short plant that makes yellow, wrinkled peas in the F2?
Pure breeding plant is one that is homozygous for the allele.
Genotype of a purebreeding plant with tall, green and wrinkled pea phenotypes is
TTyyrr
Genotype of a purebreeding plant with short and makes yellow, round peas phenotypes is
ttYYRR
F1 cross of a TTyyrr X ttYYRR cross will give TtYyRr offspring.
Since it’s a trihybrid cross (TtYyRr X TtYyRr) is difficult to show in a Punnet square (64 boxes), we use th forked-line method to calculate the probability
Each monohybrid cross give 3: 1 phenotypic ratio
The genetic probabilities are determined by multiplying together the probabilities of each phenotype.
Tall/Dwarf Round or Wrinkled Yellow or green Observed product Phenotype
¾ tall ¾ round ¾ yellow (3/4) * (3/4)*(3/4) 27/64 tall, round, yellow
¼ green (3/4) * (3/4)*(1/4) 9/64 tall, round, green
¼ Wrinkled ¾ yellow (3/4) * (1/4)*(3/4) 9/64 tall, wrinkled, yellow
¼ green (3/4) * (1/4)*(1/4) 3/64 tall, wrinkled , green
¾ short ¾ round ¾ yellow (1/4) * (3/4)*(3/4) 9/64 short, round, yellow
¼ green (1/4) * (3/4)*(1/4) 3/64 short, round, green
¼ Wrinkled ¾ yellow (1/4)*(1/4)*(3/4) 3/64 short, wrinkled, yellow
¼ green (1/4) * (1/4)*(1/4) 1/64 short, wrinkled, green
Probability of obtaining short plant that makes yellow, wrinkled peas in the F2 (short, wrinkled green) is 3/64.