Question

In: Biology

4.In dancing bears, short fur is dominant to long fur, and curly hair is dominant to...

4.In dancing bears, short fur is dominant to long fur, and curly hair is dominant to straight. The genes for these traits are located on separate autosomes.

You have a large population of dancing bears with the following allele frequencies

Short fur (S) p = 0.5, Long fur (s) q = 0.5

Curly hair (C) p = 0.3, Straight hair (c) q = 0.7

You allow the population to randomly breed for several generations. You have a population of 1000 dancing bears and count 510 with curly hair.

Is this population in Hardy-Weinberg equilibrium for this trait based on the starting allele frequencies?

Multiple Choice

a.No, that is not enough with curly hair.

b.No, that is too many with curly hair.

c.Yes.

5.In dancing bears, short fur is dominant to long fur, and curly hair is dominant to straight. The genes for these traits are located on separate autosomes.

You have a large population of dancing bears with the following allele frequencies

Short fur (S) p = 0.5, Long fur (s) q = 0.5

Curly hair (C) p = 0.3, Straight hair (c) q = 0.7

You allow the population to randomly breed for several generations. You have a population of 1000 dancing bears and count 255 with short, curly fur.

Is this population in Hardy-Weinberg equilibrium for these traits based on the starting allele frequencies?

Multiple Choice

a.No, that is not enough with short, curly hair.

b.Yes.

c.No, that is too many with short, curly fur.

6.A species of plant that grows on rock outcrops produces a chemical on its stigmas that prevents pollen germination. After collecting pollen over the course of a day, the chemical wears off and all the pollen grains germinate at once with the fastest growing male fertilizing all or most of the eggs in the ovary.

You conduct an experiment where you mix equal amounts of pollen from three different plants and place it on the stigmas of three separate flowers on six different plants. You count the number of seeds produced by each flower and use genetic tests to determine paternity of the seeds.

You think that the same male plant will fertilize the most seeds on all of the female plants. If so, this is an example of disruptive selection.

Multiple Choice

a.True.

b.False.

Solutions

Expert Solution

Answer 4 :- first we have to calculate the frequency of curly hair

Total population is 1000

Curly hair = 510,

Straight hair = 1000- 510= 490

The allele frequency of C =           total curly / total population = 510/1000=0.51

As we compare our frequency with given frequency [0.3] , we conclude that it is not matched so this population is not in Hardy-Weinberg equilibrium. so selsct Answer B

•Answer 5 :-

Answer 5:- first we have to calculate the frequency of curly hair

Total population is 1000

Curly hair = 225

The frequency of C =           total curly / total population = 225/1000=0.225

As we compare our frequency with given frequency [0.3] , we conclude that it is lower than the given , so this population is not in Hardy-Weinberg equilibrium.

to calculate the frequency of short fur

Total population is 1000

short fur = 225

The frequency of S =           total short / total population = 225/1000=0.225

As we compare our frequency with given frequency [0.3] , we conclude that it is lower than the given , so this population is not in Hardy-Weinberg equilibrium.

•Your answer is option A, not enough with short and curly fur

we can solve this problem by a different veiw - on the basis of Mende'l third law.

here we have to consider both the traits at a time -short, curly

According to Mendel's law it is dihybrid cross.

The phenotype ratio predicted for dihybrid cross is 9:3:3:1. Of the sixteen possible allele combinations: Nine combinations produce offspring with both dominant phenotypes. Three combinations each produce offspring with one dominant and one recessive phenotype.

Here short, curly both are dominant phenotype so it should in 9/16 ration.

According to above the frequency of short, curly may be = 9/16 = 0.56

In given problem 225 short, curly are produced out of 1000 so frequency may be= 225/1000= 0.225

Which is lower than actual on so Your answer is option A, not enough with short and curly fur


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