In: Statistics and Probability
In a sample of 32 elementary algebra students 8 suffered from math anxiety. Find a 98% confidence interval for the proportion of all elementary algebra students who have math anxiety.
Solution :
Given that,
n = 32
x = 8
Point estimate = sample proportion =
= x / n = 8/32=0.25
1 -
= 1-.25 =0.75
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
Z/2
= Z0.01 = 2.326 ( Using z table )
Margin of error = E = Z
/ 2 *(
((
* (1 -
)) / n)
= 2.326 (((0.25*0.75)
/32 )
E = 0.178
98% confidence interval for the proportion of all elementary is
- E < p <
+ E
0.25 - 0.178 < p < 0.25+0.178
0.072<p<0.428
(0.072 , 0.428)