Question

In: Chemistry

Finding the volume of a flask. A student obtained a clean dry glass-stoppered flask.

 

1. Finding the volume of a flask. A student obtained a clean dry glass-stoppered flask. She weighed the flask and stopper on an analytical balance and found the total mass to be 31.601 g. She then filled the flask with water and obtained a mass for the full stoppered flask of 60.735 g. From these data, and the fact that at the temperature of the used water its density is 0.9973 g/cm3, find the volume of the stoppered flask.

a. First we need to obtain the mass of the water in the flask. This is found by recognizing that the mass of a sample is equal to the sum of the masses of its parts. For the filled stoppered flask:

(Mass of filled stoppered flask) = (mass of empty stoppered flask) + (mass of water), so (mass of water) = (mass of filled flask) – (mass of empty flask).

Calculate the mass of water.

Mass of water = ___________________ g - _______________ g = _________________ g

b. The density of a pure substance is equal to its mass divided by its volume: density = (mass/volume) or volume = (mass/density).

The volume of the flask is equal to the volume of the water it contains. Since we know the mass and density of the water, we can find its volume and that of the flask. Calculate the volume of the flask.

(Volume of water) = (volume of flask) = ________________ cm3

2. Finding the density of an unknown liquid. Having obtained the volume of the flask, the student emptied the flask, dried it, and filled it with an unknown whose density she wished to determine. The mass of the stoppered flask when completely filled with liquid was 56.796 g. Find the density of the liquid.

a. First we need to find the mass of the liquid by measuring by difference:

(Mass of liquid) = __________________ g - _______________________ g = ____________________ g

b. Since the volume of the liquid equals that of the flask, we know both the mass and volume of the liquid and can easily find its density using the equation in 1b. Make the calculation.

(Density of liquid) = _________________ g/cm3

3. Finding the density of a solid. The student then emptied the flask and dried it once again. To the empty flask she added pieces of metal until the flask was about half full. She weighed the stoppered flask and its metal contents and found that the mass was 99.323 g. She then filled the flask with water, stoppered it, and obtained a total mass of 120.827 g for the flask, stopper, metal, and water. Find the density of the metal.

a. To find the density of the metal we need to know its mass and volume. We can easily obtain is mass by the method of differences:

(Mass of metal) = ________________ g - _____________________ g = ___________________ g

b. To determine the volume of metal, we note that the volume of the flask must equal the volume of the metal plus the volume of water in the filled flask containing both metal and water. If we can find the volume of water, we can obtain the volume of metal by the method of differences. To obtain the volume of the water we first calculate its mass:

Mass of water = mass of (flask + stopper + metal + water) – mass of (flask + stopper + metal)

Mass of water = ______________ g - ____________________ g = __________________ g

The volume of water is found from its density, as in 1b. Make the calculation.

Volume of water = _____________________ cm3
c. From the volume of the water we calculate the volume of metal:

cm3

Volume of metal = volume of flask – volume of water
Volume of metal = _________________ cm3 - __________________ cm3 = __________________

From the mass and volume of the metal we find the density, using the equation in 1b. Make the calculation.

Density of metal = _____________________ g/cm3

Solutions

Expert Solution


Related Solutions

Why is it acceptable to use a clean, wet volumetric flask, instead of a clean, dry...
Why is it acceptable to use a clean, wet volumetric flask, instead of a clean, dry volumetric flask, when you are preparing your standard solutions by dilution? Explain in detail.
Exactly 25.0 ml of 0.060 M Benzoic acid was placed in a clean dry Erlenmeyer flask...
Exactly 25.0 ml of 0.060 M Benzoic acid was placed in a clean dry Erlenmeyer flask and titrated with 0.075 M NaOH solution. Determine the pH of the solution in the flask after each of the following amounts of the NaOH solution is added if the Ka of the benzoic acid is 6.3 x 10-5 f.) 20.00 ml NaOH g.) 20.10 ml NaOH h.) 25.00 ml NaOH i.) 30.00 ml NaOH
CLEAN & DRY You are conducting the annual financial statement audit engagement of Clean & Dry,...
CLEAN & DRY You are conducting the annual financial statement audit engagement of Clean & Dry, a large dry cleaning operation with 100 outlets all across Canada. Clean & Dry is 100% owned by Bob Clarke. This is the first time you have worked on the Clean & Dry engagement. However, they have been your firm’s client for the past five years. You know, however, from previous audit engagements in which chemicals are used, that there is an environmental risk...
A student needs to determine the volume occupied by a gas in a 125 mL flask...
A student needs to determine the volume occupied by a gas in a 125 mL flask using the experimental setup described in the procedure. The student measures the volume of the flask to be 156 mL to the top of the flask. The student measures the volume of the flask with a stopper in it to be 138 mL. The student performs the experiment by reacting the strip of magnesium with 5 mL of HCl solution. What is the volume...
Procedure Reaction 1: Dissolving the Copper 1. Obtain a clean, dry, glass centrifuge tube. 2. Place...
Procedure Reaction 1: Dissolving the Copper 1. Obtain a clean, dry, glass centrifuge tube. 2. Place a piece of copper wire in a weighing paper, determine the mass of the wire and place it in the centrifuge tube. The copper wire should weigh less than 0.0200 grams. 3. In a fume hood, add seven drops of concentrated nitric acid to the reaction tube so that the copper metal dissolves completely. Describe your observations in the lab report. (Caution, Concentrated nitric...
A student dissolved 0.946g Al in 35mL of 2.00M KOH and obtained 13.8g of dry alum...
A student dissolved 0.946g Al in 35mL of 2.00M KOH and obtained 13.8g of dry alum by following the experimental procedure given in this exercise. Assume that the Alum was 97.7% pure. 1. Calculate the theoretical and actual % yield. 2. Calculate the volume of excess KOH(aq) and the volume of 6.00M H2SO4(aq) needed to neutralize it. 3. Calculate the volume of 6.00M H2SO4(aq) needed just to precipitate Al(OH)3(s). 4. Calculate the volume of 6.00M H2SO4(aq) needed just to dissolve...
In a student experiment, a constant-volume gas thermometer is calibrated in dry ice (−78.5°C) and in...
In a student experiment, a constant-volume gas thermometer is calibrated in dry ice (−78.5°C) and in boiling ethyl alcohol (78°C). The separate pressures are 0.896 atm and 1.629 atm. Hint: Use the linear relationship P = A + BT, where A and B are constants. (a) What value of absolute zero does the calibration yield? (b) What pressure would be found at the freezing point of water? (c) What pressure would be found at the boiling point of water?
A dry cleaner in California encountered controversy for charging more to dry clean women’s shirts than...
A dry cleaner in California encountered controversy for charging more to dry clean women’s shirts than men’s shirts. As an unhappy female customer noted, “They charged me $1.50 for each of my husband’s shirts, and he wears an extra large. They charged $3.50 for each of mine, and I wear a small.” The store owner explained that the difference stemmed from the need to hand iron her shirts because his automatic presser was not made to handle small-sized women’s garments....
A student recorded the mass of a glass bead to be 0.7691g. If glass has a...
A student recorded the mass of a glass bead to be 0.7691g. If glass has a denisty of 0.85g/mL, what would the diameter, in mm, of the glass bead be?
b. When the volume of the flask is determined, the mass of the air is not...
b. When the volume of the flask is determined, the mass of the air is not important. Explain why. c. Explain why we consider the mass of the air in the"empty" flask when we are calculating the mass of the flask(Equation 8), but we do not consider the mass of air when calculating the volume of CO2(Equation 6). 2. At STP, what volume of CO2 could be generated from 3.0 g of marble chips? 3. At ordinary lab conditions of...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT