In a recent survey of 200 elementary students, many revealed they preferred math than English. Suppose...

In a recent survey of 200 elementary students, many revealed they preferred math than English. Suppose that 80 of the students surveyed were girls and that 120 of them were boys. In the survey, 60 of the girls, and 80 of the boys said that they preferred math more.

1. What is the difference in the probability between that girls prefer math more and boys prefer math more?

a.0.0833

b. 0.5

c 0.0042

d. 0.4097

2. What is the standard error of the difference in the probability between that girls prefer math more and boys prefer math more?

a.0.4097

b.0.0042

c. 0.0833

d. 0.0647734

3. Calculate an 80% confidence interval for the difference in proportions

4. Suppose the 90% confidence interval for the difference in proportion is (-0.0232, 0.1899).

Is the following interpretation of the confidence interval true?

"For all elementary students, I have 90% confidence that the true proportion difference between girls and boys is in the interval (-0.0232, 0.1899)."

Solutions

Expert Solution

Solution-

n=200

n(girls)= 80

n(boys) = 120

orchestra answered 1 year ago

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