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In: Statistics and Probability

In a trial of Pfizer’s new math-anxiety-reducing drug, a random sample of 100 students yielded 58...

In a trial of Pfizer’s new math-anxiety-reducing drug, a random sample of 100 students yielded 58 who showed significant improvement. Construct a 92% confidence interval for π, the population proportion of all students who would be helped by the drug. (Round to two decimals places)

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Expert Solution

We have given here,                          
                          
x=58                      
n=100                      
Estimate for sample proportion                          

Level of significance is =1-0.92=0.08                  
Z critical value(using Z table)=1.751                  

Therefore, 92% confidence interval for population proportion is =(0.49, 0.67)

orchestra answered 1 year ago
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