A woman of mass m = 58.9 kg sits on the left end of a seesaw—a...

A woman of mass m = 58.9 kg sits on the left end of a seesaw—a plank of length L = 4.04 m, pivoted in the middle.

(a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 69.9 kg sit if the system (seesaw plus man and woman) is to be balanced?
1.702m (Correct)

(b) Find the normal force exerted by the pivot if the plank has a mass of m_pl = 12.8 kg.
1387.68N (Correct)

(c) Repeat part (a), but this time compute the torques about an axis through the left end of the plank.
1.65m (Correct)

QUESTION: Suppose a 27.8-kg child sits 0.73 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced.

(a) Find the mass of the second child 10.05 kg?

(b) Find the normal force acting at the pivot point.____N?

Expert Solution

genius_generous answered 1 year ago

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