In: Physics
Moment of Inertia along diameter and passing through its centre of mass is given by
where
M is mass of solid sphere
R is radius of solid sphere
Above is diagram of solid sphere where O is its centre of Mass and A is a point at a distance R through which an axis parallel to COM axis is passing
Now we need to find Moment of Inertia along axis passing through point A using Parallel Axis theorem which says
Given information
Mass of solid sphere = M = 0.324 Kg
Radius of solid sphere = R = 0.245 m
Frequency of rotation = v = 42.6 Hz
As mentioned in problem that solid sphere rotates without slipping, thus work done will be same as Rotational Kinetic Energy for solid sphere
work done = W= 973.37 J