In: Chemistry
1)Given the following data: 2H2(g) + O2(g) → 2H2O(l) ΔH = -571.6 kJ CO2(g) + 2H2O(l) → CH4(g) + 2O2(g) ΔH = +890.3 kJ C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ Find the ΔH of the following reaction: C(s) + 2H2(g) → CH4(g)
2H2(g) + O2(g) 2H2O(l) H1= -571.6KJ 1st equation
CO2(g) + 2H2O(l) → CH4(g) + 2O2(g) ΔH2 = +890.3 kJ 2nd equation
C(s) + O2(g) → CO2(g) ΔH3 = -393.5 kJ 3rd equation
we required
C(s) + 2H2(g) → CH4(g) H=?
if we add 1st + 2nd + 3rd equation
2H2(g) + O2(g) 2H2O(l) H1= -571.6KJ
CO2(g) + 2H2O(l) → CH4(g) + 2O2(g) ΔH2 = +890.3 kJ
C(s) + O2(g) → CO2(g) ΔH3 = -393.5 kJ
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then we easly get required equation
C(s) + 2H2(g) → CH4(g) H=H1+H2+H3
H=-571.6KJ +890.3 kJ -393.5 kJ = -74.8KJ