In: Chemistry
Calculate ΔHrxn for the following reaction:
CH4(g)+2O2(g)→CO2(g)+2H2O(l)
Use the following reactions and given ΔH values.
CH4(g)+O2(g)→CH2O(g)+H2O(g),
ΔH=−284 kJ
CH2O(g)+O2(g)→CO2(g)+H2O(g),
ΔH=−527 kJ
H2O(l)→H2O(g), ΔH= 44.0 kJ
Please, provide thorough explanation
CH4(g)+O2(g)→CH2O(g)+H2O(g),
ΔH=−284 kJ -------------> 1
CH2O(g)+O2(g)→CO2(g)+H2O(g),
ΔH=−527 kJ --------------> 2
H2O(l)→H2O(g), ΔH= 44.0 kJ
------------->3
adding 1 and 2 equations
CH4(g)+O2(g)→CH2O(g)+H2O(g),
ΔH=−284 kJ -------------> 1
CH2O(g)+O2(g)→CO2(g)+H2O(g),
ΔH=−527 kJ --------------> 2
-----------------------------------------------------------------------------------------------------------
CH4(g) + 2O2(g) ---------> CO2 (g) + 2H2O(g) ΔH = -811KJ
2H2O(l) ------------------------> 2H2O (g) ΔH = 88KJ substact
(-) (-) (-)
------------------------------------------------------------------------------------------------------------
CH4(g)+2O2(g)--------------------> CO2(g)+2H2O(l) ΔH = -899KJ