Question

In: Chemistry

2Br–(aq) + 2H+(aq) + CO2(g) → Br2(aq) + HCOOH(aq) The concentration of the Br- falls from...

2Br–(aq) + 2H+(aq) + CO2(g) → Br2(aq) + HCOOH(aq)

The concentration of the Br- falls from 0.120M to 0.080 M in 15 s. Calculate the amount of Br2(l) formed during the same time interval.

Solutions

Expert Solution


Related Solutions

Calculate the Eocell for: Fe(s) + Br2(g) →   Fe2+(aq) +Br-(aq) ; is this electrolytic or voltaic?...
Calculate the Eocell for: Fe(s) + Br2(g) →   Fe2+(aq) +Br-(aq) ; is this electrolytic or voltaic? A. -1.52V ; voltaic B. 1.52V ; electrolytic C. -1.52V ; electrolytic D. 1.52V ; voltaic
The standard cell potential, E°, for Br2(aq) + Zn(s) → 2Br-(aq) + Zn2+(aq) at 298K is...
The standard cell potential, E°, for Br2(aq) + Zn(s) → 2Br-(aq) + Zn2+(aq) at 298K is 1.82V. Calculate the value of ΔG° in kJ. Use 96,485 C/mol e-. Then calculate the equilibrium constant for the data.
Consider the following three-step mechanism for a reaction: Br2 (g) ⇌ 2 Br (g) Fast Br...
Consider the following three-step mechanism for a reaction: Br2 (g) ⇌ 2 Br (g) Fast Br (g) + CHBr3 (g) → HBr (g) + CBr3 (g) Slow Br (g) + CBr3 (g) → CBr4 (g) Fast Based on this mechanism, determine the rate law for the overall reaction. Rate =  
Ca(s)+2H(aq)--> Ca^2+(aq)+H2        ∆H= -543 KJ/mol CaCO3(s)+2H(aq)-->Ca^2+(aq)+CO2(g)+H2O(l)      ∆H= -15 KJ/mol Look up the heats formation for CO2...
Ca(s)+2H(aq)--> Ca^2+(aq)+H2        ∆H= -543 KJ/mol CaCO3(s)+2H(aq)-->Ca^2+(aq)+CO2(g)+H2O(l)      ∆H= -15 KJ/mol Look up the heats formation for CO2 and H2O in the thermodynamic tables and use this information along with the above heats of reaction to calculate the standard enthalpy of formation for CaCO3. Write the balanced equations for the two heat of formations reactions, and use Hess Law in order to answer this question.
Consider the following reaction: Br2(l) + 2I-(aq) ---> 2Br-(aq) + I2(s) a.Calculate ΔGorxn b.Calculate K
Consider the following reaction: Br2(l) + 2I-(aq) ---> 2Br-(aq) + I2(s) a.Calculate ΔGorxn b.Calculate K
Pd/Pd2+ (aq, 0.00010M)/ Br2 (l), Br-(aq, 0.00010M)/Pt(s) What is the Ecell?
Pd/Pd2+ (aq, 0.00010M)/ Br2 (l), Br-(aq, 0.00010M)/Pt(s) What is the Ecell?
Half-reaction E° (V) Br2(l) + 2e- 2Br-(aq) 1.080V Sn2+(aq) + 2e- Sn(s) -0.140V Al3+(aq) + 3e-...
Half-reaction E° (V) Br2(l) + 2e- 2Br-(aq) 1.080V Sn2+(aq) + 2e- Sn(s) -0.140V Al3+(aq) + 3e- Al(s) -1.660V (1) The weakest oxidizing agent is: enter formula (2) The strongest reducing agent is: (3) The strongest oxidizing agent is: (4) The weakest reducing agent is: (5) Will Al(s) reduce Br2(l) to Br-(aq)? (6) Which species can be oxidized by Sn2+(aq)? If none, leave box blank.
What is the standard Gibb’s Free Energy of the reaction graphite | Br-(aq) | Br2(l) |...
What is the standard Gibb’s Free Energy of the reaction graphite | Br-(aq) | Br2(l) | | I2(s) | I-(aq)? Is the reaction spontaneous under standard conditions? What is the initial cell potential of the voltaic cell represented by Zn | Zn+2 [0.100 M) | | Ni+2 (1.50 M) | Ni ? b. What is the cell potential when [Ni+]=0.500 M? c. What are the metal ion concentrations when the cell potential has fallen to 0.45 V?
Consider the equilibrium shown. PbBr2(s)−⇀↽− Pb2+(aq)+2Br−(aq)Ksp=2.10×10−6 Determine the concentrations of Pb2+ and Br− in a saturated...
Consider the equilibrium shown. PbBr2(s)−⇀↽− Pb2+(aq)+2Br−(aq)Ksp=2.10×10−6 Determine the concentrations of Pb2+ and Br− in a saturated solution of PbBr2 in pure water (assume μ=0 M). [Pb2+]= M [Br−]= M Determine the concentrations of Pb2+ and Br− in a saturated solution of PbBr2 in a solution with an ionic strength of 0.010 M. [Pb2+]= M [Br−]= M Determine the concentrations of Pb2+ and Br− in a saturated solution of PbBr2 in a solution with an ionic strength of 0.10 M. [Pb2+]=...
Balance the following redox reaction in acidic solution. Br? (aq) + MnO2 (s) ? Br2 (l)...
Balance the following redox reaction in acidic solution. Br? (aq) + MnO2 (s) ? Br2 (l) + Mn+2 (aq)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT