Calculate the Eocell for: Fe(s) + Br2(g)
→ Fe2+(aq) +Br-(aq) ; is this
electrolytic or voltaic?
A.
-1.52V ; voltaic
B.
1.52V ; electrolytic
C.
-1.52V ; electrolytic
D.
1.52V ; voltaic
The standard cell potential, E°, for Br2(aq) + Zn(s)
→ 2Br-(aq) + Zn2+(aq) at 298K is 1.82V.
Calculate the value of ΔG° in kJ. Use 96,485 C/mol e-.
Then calculate the equilibrium constant for the data.
Consider the following three-step mechanism for a
reaction:
Br2 (g) ⇌ 2 Br (g) Fast
Br (g) + CHBr3 (g) → HBr (g) + CBr3 (g)
Slow
Br (g) + CBr3 (g) → CBr4 (g) Fast
Based on this mechanism, determine the rate law for the overall
reaction.
Rate =
. Consider the following reduction-oxidation “skeleton”
equation,
Br2(l) = BrO3 ‒ (aq) + Br‒ (aq)
a. Write a balanced equation for the reduction-oxidation
reaction that occurs in basic solution.
b. Using your balanced equation, identify the chemical species
that is: (1) oxidized, (2) reduced, (3) the reducing agent, and (4)
the oxidizing agent.
Ca(s)+2H(aq)-->
Ca^2+(aq)+H2 ∆H= -543
KJ/mol
CaCO3(s)+2H(aq)-->Ca^2+(aq)+CO2(g)+H2O(l)
∆H= -15 KJ/mol
Look up the heats formation for CO2 and H2O in the thermodynamic
tables and use this information along with the above heats of
reaction to calculate the standard enthalpy of formation for CaCO3.
Write the balanced equations for the two heat of formations
reactions, and use Hess Law in order to answer this question.
Half-reaction E° (V) Br2(l) + 2e- 2Br-(aq) 1.080V
Sn2+(aq) + 2e- Sn(s) -0.140V
Al3+(aq) + 3e- Al(s) -1.660V
(1) The weakest oxidizing agent is: enter formula (2) The
strongest reducing agent is: (3) The strongest oxidizing agent is:
(4) The weakest reducing agent is: (5) Will Al(s) reduce Br2(l) to
Br-(aq)? (6) Which species can be oxidized by Sn2+(aq)? If none,
leave box blank.
What is the standard Gibb’s Free Energy of the reaction graphite
| Br-(aq) | Br2(l) | |
I2(s) | I-(aq)? Is the
reaction spontaneous under standard conditions?
What is the initial cell potential of the voltaic cell
represented by Zn | Zn+2 [0.100 M) | | Ni+2
(1.50 M) | Ni ?
b. What is the cell potential when [Ni+]=0.500 M?
c. What are the metal ion concentrations when the cell potential
has fallen to 0.45 V?
Consider the equilibrium shown.
PbBr2(s)−⇀↽− Pb2+(aq)+2Br−(aq)Ksp=2.10×10−6
Determine the concentrations of Pb2+ and Br− in a saturated
solution of PbBr2 in pure water (assume μ=0 M).
[Pb2+]=
M
[Br−]=
M
Determine the concentrations of Pb2+ and Br− in a saturated
solution of PbBr2 in a solution with an ionic strength of 0.010
M.
[Pb2+]=
M
[Br−]=
M
Determine the concentrations of Pb2+ and Br− in a saturated
solution of PbBr2 in a solution with an ionic strength of 0.10
M.
[Pb2+]=...