Question

In: Chemistry

Consider the equilibrium shown. PbBr2(s)−⇀↽− Pb2+(aq)+2Br−(aq)Ksp=2.10×10−6 Determine the concentrations of Pb2+ and Br− in a saturated...

Consider the equilibrium shown.

PbBr2(s)−⇀↽− Pb2+(aq)+2Br−(aq)Ksp=2.10×10−6

Determine the concentrations of Pb2+ and Br− in a saturated solution of PbBr2 in pure water (assume μ=0 M).

[Pb2+]=

M

[Br−]=

M

Determine the concentrations of Pb2+ and Br− in a saturated solution of PbBr2 in a solution with an ionic strength of 0.010 M.

[Pb2+]=

M

[Br−]=

M

Determine the concentrations of Pb2+ and Br− in a saturated solution of PbBr2 in a solution with an ionic strength of 0.10 M.

[Pb2+]=

M

[Br−]=

Solutions

Expert Solution

Solution : Calculation are given below in images . For any query please comment below.


Related Solutions

Determine the concentrations of Pb2 and Br– in a saturated solution of PbBr2 in: a) pure...
Determine the concentrations of Pb2 and Br– in a saturated solution of PbBr2 in: a) pure water (assume μ = 0). b) a solution with an ionic strength of 0.010. c) a solution with an ionic strength of 0.10.
Saturated solution of PbBr2 in .20M of CaBr2 solution. Ksp = PbBr2 = 4.67x10^-6 Need ionization...
Saturated solution of PbBr2 in .20M of CaBr2 solution. Ksp = PbBr2 = 4.67x10^-6 Need ionization equation and Molar solubility.
a. The Ksp for PbBr2 = 6.60 X 10-6. What is the molar solubility of PbBr2...
a. The Ksp for PbBr2 = 6.60 X 10-6. What is the molar solubility of PbBr2 in a 1.40M solution of aluminum bromide? b. The Ksp for manganese (II) hydroxide = 2.0 X 10-13. What is the molar solubility of manganese (II) hydroxide in a 3.60M solution of ammonia?
Data given - PbI2(s) <===> Pb2+(aq) + 2I- (aq) ( Ksp = [Pb2+][I-]2 ) 5.0mL 0.0120...
Data given - PbI2(s) <===> Pb2+(aq) + 2I- (aq) ( Ksp = [Pb2+][I-]2 ) 5.0mL 0.0120 M Pb(NO3)2 2.0 mL 0.0300 M KI 3.0 mL 0.20 M KNO3 Total volume = 10 mL Absorbance of solution = 0.280 [ I- ] in moles/liter at equilibrium = 4.2 CALCULATE - a) The initial no. of moles Pb2+ Answer b) The initial no. of moles I- c) No. of moles I- at equilibrium d) No. moles I- precipitated e) No. moles Pb2+...
PbBr2 will be least soluble in which of the following? Ksp of PbBr2 is 4.6*10^-6. Show...
PbBr2 will be least soluble in which of the following? Ksp of PbBr2 is 4.6*10^-6. Show your calculations on the molar concentration of PbBr2 to support your answer. Options are: A) water B) 0.10 M Pb(NO3)2 C) 0.15 M KBr
Consider the following system in equilibrium: CuCO3 (s) ⇌ Cu2+ (aq) + CO3 2- (aq) Ksp...
Consider the following system in equilibrium: CuCO3 (s) ⇌ Cu2+ (aq) + CO3 2- (aq) Ksp = 1.4 x10-10 CO2 (g) ⇌ CO2 (aq) K1 = 3.4 x10-2 CO2 (aq) + H2O (l) ⇌ HCO3 - (aq) + H+ (aq) K2 = 4.7 x10-7 HCO3 - (aq) ⇌ CO3 2- (aq) + H+ (aq) K3 = 5.1 x10-11 At equilibrium, the pH of the solution is equal to 5.745 when the system is saturated with CuCO3. In standard conditions (pressure...
Consider the following system in equilibrium: CuCO3 (s) ⇌ Cu2+ (aq) + CO3 2- (aq) Ksp...
Consider the following system in equilibrium: CuCO3 (s) ⇌ Cu2+ (aq) + CO3 2- (aq) Ksp = 1.4 x10-10 CO2 (g) ⇌ CO2 (aq) K1 = 3.4 x10-2 CO2 (aq) + H2O (l) ⇌ HCO3 - (aq) + H+ (aq) K2 = 4.7 x10-7 HCO3 - (aq) ⇌ CO3 2- (aq) + H+ (aq) K3 = 5.1 x10-11 At equilibrium, the pH of the solution is equal to 5.745 when the system is saturated with CuCO3. In standard conditions (pressure...
Ksp for PbBr2 is equal to: 4.67 x 10^-6. How many grams of PbBr2 will dissolve...
Ksp for PbBr2 is equal to: 4.67 x 10^-6. How many grams of PbBr2 will dissolve in 250.0 mL of solution? (Molar mass of PbBr2 = 367.01 g/mol)
The Ksp of PbBr2 is 6.60*10^-6 M^3. What is the molar solubility of PbBr2 in pure...
The Ksp of PbBr2 is 6.60*10^-6 M^3. What is the molar solubility of PbBr2 in pure water? What is the molar solubility of PbBr2 in 0.500 M KBr solution? What is the molar solubility of PbBr2 in 0.500 M Pb(NO3)2 solution?
Find Ksp for AgCl(s) where Ksp is the equilibrium consstant for AgCl(s)<=> Ag+ (aq) + Cl-(aq)...
Find Ksp for AgCl(s) where Ksp is the equilibrium consstant for AgCl(s)<=> Ag+ (aq) + Cl-(aq) dG respectively is -109.70, 77.11, -131.2 kj for mol. Answer: 1.8x10^-10 and what is the partial pressure of atomic chlorine that would be at equilibrium with Cl2(g) at 25*C and 1 atm? delta G =105.7 kJ mol-1. Answer: 3.0 x 10^-19.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT