The standard cell potential, E°, for Br2(aq) + Zn(s) → 2Br-(aq) + Zn2+(aq) at 298K is...

The standard cell potential, E°, for Br₂(aq) + Zn(s) → 2Br^-(aq) + Zn²⁺(aq) at 298K is 1.82V. Calculate the value of ΔG° in kJ. Use 96,485 C/mol e^-. Then calculate the equilibrium constant for the data.

Solutions

Expert Solution

Br₂(aq) + Zn(s) → 2Br^-(aq) + Zn²⁺(aq) E⁰ = 1.82v

Zn(s) -------------------> Zn^2+ (aq) + 2e^- E⁰ = 0.76v

Br2(aq) + 2e^- ----------------> 2Br^- (aq) E⁰ = 1.06v

----------------------------------------------------------------------------------------

Br₂(aq) + Zn(s) → 2Br^-(aq) + Zn²⁺(aq) E⁰ = 1.82v

n = 2

ΔG° = -nE⁰ * F

= -2*1.82*96485

= -351205J

ΔG° = -RTlnK

-351205 = -8.314*298*2.303logK

logK = -351205/-5705.8483

logK = 61.55

K = 10^61.55 = 3.63*10^61 >>>>answer

queen_honey_blossom answered 1 year ago

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