Leave the index of refraction of the upper medium at 1.00 and of the lower medium...

Leave the index of refraction of the upper medium at 1.00 and of the lower medium at 1.35. Change the incident angle θ1 to different angles between 0o and 90o and note the direction θ1' of the reflected ray. Devise a rule that relates the incident and the reflected angles.

Expert Solution

Data Table

So as the angle of incidence increases angle of refraction also increases. lets try to calculate the ratio's of Sine of and Sine of

For first reading

Which is nearly equal to the refractive index of the medium, So we can conclude that

where n is the refractive index of the denser medium.

genius_generous answered 3 years ago

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