The glass core of an optical fiber has an index of refraction 1.60. The index of...

The glass core of an optical fiber has an index of refraction 1.60. The index of refraction of the cladding is 1.49.

A) What is the maximum angle a light ray can make with the wall of the core if it is to remain inside the fiber?

Express your answer with the appropriate units.

Solutions

Expert Solution

From Snell's Law we have n1 * sin(theta) = n2 * sin(90) = n2

so theta = arcsin(n2/n1)

= arcsin(1.49 / 1.60) = 68.63 degree

But this angle is measured from the normal so from the wall the angle

= 90 -68.63 = 21.37 degree

genius_generous answered 1 year ago

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