In: Statistics and Probability
A random sample of 100 observations produced a sample mean of 32. Find the critical and observed values of z for the following test of hypothesis using α = 0.025 . The population standard deviation is known to be 5 and the population distribution is normal. H 0 : μ = 28 versus H 1 : μ ≠ 28 .
Given that the random sample of n = 100 observations produced a
sample mean of
= 32, the population standard deviation is known to be
= 5, and the population distribution is normal.
Given the Hypotheses are:
Ho : μ = 28
H1: μ ≠ 28
Based on the hypothesis it will be a two-tailed test and since the population standard deviation is known hence Z-distribution is applicable.
Test Statistic:
The calculated test Statistic will be:
Critical value:
The critical value for rejection fo the null hypothesis is
calculated using excel formula for normal distribution which is
-NORM.S.INV(1-/2)
hence the formula used is =NORM.S.INV(1-0.025/2), thus the Z
critical is computed as Zc = +/- 2.24
P-value:
The P-value is computed using excel formula for normal distribution or by Z table but since the Z score is very high so, P-value will be =0.
Conclusion:
Since P-value is less than 0.025 hence we reject the Null hypothesis.
The Z table is attached below: