In: Statistics and Probability
Let the continuous random variable D denote the diameter of the
hole drilled in an
aluminum sheet. The target diameter to be achieved is 12.5mm.
Random
disturbances in the process often result in inaccuracy.
Historical data shows that the distribution of D can be modelled by
the PDF, f(d) =
20e−20(d−12.5), d ≥ 12.5. If a part with diameter > 12.6 mm
needs to be scrapped,
what is the proportion of those parts? What is the CDF when the
diameter is of 11
mm?
What is the conclusion of this experiment?
Problem Statement 10:
Please compute the following:
a) P(Z > 1.26), . P(Z < −0.86), P(Z > −1.37), P(−1.25 <
Z < 0.37), . P(Z ≤ −4.6)
b) Find the value z such that P(Z > z) = 0.05
c) Find the value of z such that P(−z < Z < z) = 0.99