Question

In: Statistics and Probability

Let x be a continuous random variable that is normally distributed with a mean of 65...

  1. Let x be a continuous random variable that is normally distributed with a mean of 65 and a standard deviation of 15. Find the probability that x assumes a value:

  1. less than 48

  1. greater than 87

           

  1. between 56 and 70

Solutions

Expert Solution

This is a normal distribution question with



a) P(x < 48.0)=?
The z-score at x = 48.0 is,

z = -1.1333
This implies that



b) P(x > 87.0)=?
The z-score at x = 87.0 is,

z = 1.4667
This implies that
P(x > 87.0) = P(z > 1.4667) = 1 - 0.92877115855788




c) P(56.0 < x < 70.0)=?

This implies that
P(56.0 < x < 70.0) = P(-0.6 < z < 0.3333) = P(Z < 0.3333) - P(Z < -0.6)
P(56.0 < x < 70.0) = 0.6305460803074295 - 0.2742531177500736

PS: you have to refer z score table to find the final probabilities.
Please hit thumbs up if the answer helped you


Related Solutions

A. Let x be a continuous random variable that is normally distributed with mean μ=24 and...
A. Let x be a continuous random variable that is normally distributed with mean μ=24 and standard deviation σ=4. Use a graphing calculator to find P(20≤x≤33). The probability is? (Round to 4 decimal places) B. Let x be a continuous random variable that is normally distributed with mean μ=27 and standard deviation σ=4. Use a graphing calculator to find P(19≤x≤35). The probability is? (Round to 4 decimal places) C. Let x be a continuous random variable that is normally distributed...
A random variable X is Normally distributed with mean = 75 and = 8. Let Y...
A random variable X is Normally distributed with mean = 75 and = 8. Let Y be a second Normally distributed random variable with mean = 70 and = 12. It is also known that X and Y are independent of one another. Let W be a random variable that is the difference between X and Y (i.e., W = X – Y). What can be said about the distribution of W?
Suppose a random variable X is normally distributed with mean 65 and standard deviation 7. Answer...
Suppose a random variable X is normally distributed with mean 65 and standard deviation 7. Answer the following questions: 1. P(48.90 < X < 70.60) = ____ [round to 4 decimal places] 2. P(X ≤ 65.70) = _____ [round to 4 decimal places] 3. P(X = 70.60) = ____ [round to 4 decimal places] 4.Suppose a is such that: P(X ≤ a) = 0.46. Then a = ____ [round to 2 decimal places] 5. What is the IQR (inter-quartle range)...
X is a random variable which is normally distributed with a mean of 99.01 and a...
X is a random variable which is normally distributed with a mean of 99.01 and a standard deviation of 15.56. Use the Excel function NORMINV to determine the required value of Xo to two decimal places. Give your answer in the form xx.xx. P(X < Xo) = 0.0344 Answer:
Let X be a continuous random variable following normal distribution with mean value of: (a is...
Let X be a continuous random variable following normal distribution with mean value of: (a is 1) and standard deviation of b is 1/10 ,  What is the mode of X? (1 mark)  What is median of X? (1 mark)  What is ?(? > ?)? (1mark)  What is ?(? − ? < ? < ? + ?)? (1 mark)  What is ?(? − 1.96? < ? < ? + 1.96?))? (1mark)
Let X be a continuous random variable following normal distribution with mean value of: (a is...
Let X be a continuous random variable following normal distribution with mean value of: (a is the last digit of your student number) and standard deviation of b (b is the last digit of your student number divided by 10), a=9 b=9/10 What is the mode of X? What is median of X? What is P(X>a)? What is P(a-b<X<a+b)? What is P(a-1.96b<X<a+1.96b)?
1) Let   x be a continuous random variable that follows a normal distribution with a mean...
1) Let   x be a continuous random variable that follows a normal distribution with a mean of 321 and a standard deviation of 41. (a) Find the value of   x > 321 so that the area under the normal curve from 321 to x is 0.2224. Round your answer to the nearest integer. The value of   x is_______ (b) Find the value of x so that the area under the normal curve to the right of x is 0.3745. Round...
5. X is a normally distributed random variable with a mean of 8 and a standard...
5. X is a normally distributed random variable with a mean of 8 and a standard deviation of 3. The probability that X is between 6 and 10 is a. 0.7486 b. 0.4972 c. 0.6826 d. 0.8413 The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 20 pounds. 6. The probability of a player weighing more than 240 pounds is a. 0.0197 b. 0.9803 c. 0.4803 d. 0.0228 7. Refer...
The random variable x is normally distributed with a mean of 68 and a standard deviation...
The random variable x is normally distributed with a mean of 68 and a standard deviation of 4. Find the interquartile range (IQR)? Use R.
1. Given that the random variable X is normally distributed with a mean of 30 and...
1. Given that the random variable X is normally distributed with a mean of 30 and a standard deviation of 5, determine the following: P(32.2 <X). 2. The pdf(probability distribution function) of a random variable X is given by f(x) = 3x^2 with support 0<x<1. Determine P(0.4 < X < 0.6).
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT