In: Statistics and Probability
This is a normal distribution question with
a) P(x < 48.0)=?
The z-score at x = 48.0 is,
z = -1.1333
This implies that
b) P(x > 87.0)=?
The z-score at x = 87.0 is,
z = 1.4667
This implies that
P(x > 87.0) = P(z > 1.4667) = 1 - 0.92877115855788
c) P(56.0 < x < 70.0)=?
This implies that
P(56.0 < x < 70.0) = P(-0.6 < z < 0.3333) = P(Z <
0.3333) - P(Z < -0.6)
P(56.0 < x < 70.0) = 0.6305460803074295 -
0.2742531177500736
PS: you have to refer z score table to find the final
probabilities.
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