Question

In: Statistics and Probability

Let be a continuous random variable that has a normal distribution with μ = 48 and...

Let be a continuous random variable that has a normal distribution with μ = 48 and σ = 8. Assuming , n/N ≤ 0.05, find the probability that the sample mean, x , for a random sample of 16 taken from this population will be more than 45.30 . Round your answer to four decimal places.

Solutions

Expert Solution

Solution :

Given that,

mean = = 48

standard deviation = = 8

n = 16

=   = 48

= / n = 8 / 16 = 2

P( > 45.30) = 1 - P( < 45.30)

= 1 - P[( - ) / < (45.30 - 48) / 2]

= 1 - P(z < -1.35)

Using z table,    

= 1 - 0.0885

= 0.9115


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