In: Statistics and Probability
Let be a continuous random variable that has a normal distribution with μ = 48 and σ = 8. Assuming , n/N ≤ 0.05, find the probability that the sample mean, x , for a random sample of 16 taken from this population will be more than 45.30 . Round your answer to four decimal places.
Solution :
Given that,
mean = = 48
standard deviation = = 8
n = 16
= = 48
= / n = 8 / 16 = 2
P( > 45.30) = 1 - P( < 45.30)
= 1 - P[( - ) / < (45.30 - 48) / 2]
= 1 - P(z < -1.35)
Using z table,
= 1 - 0.0885
= 0.9115