In: Chemistry
Tin metal can be obtained by the reduction of tin ions (Sn2+) by Co2+ at 298 K: Sn2+ (aq) + Co2+(aq) <--> Sn (s) + Co4+ (aq) , Kc = 1.70
150 mL of 0.200 M Sn(NO3)2 is mixed with 150 mL of 0.250 M Co(NO3)2 at 298 K. What is the concentration of Co4+ at equilibrium? SHOW ALL WORK.
concentration of Sn+2 = 150 x 0.2 / 150 + 150 = 0.1 M
concentration of Co+2 = 150 x 0.250 / 150 + 150 = 0.125 M
Sn2+ (aq) + Co2+(aq) <----------> Sn (s) + Co4+ (aq)
0.1 0.125 0
0.1 - x 0.125 - x x
Kc = x / (0.1 - x )(0.125 - x)
1.70 = x / x^2 - 0.225 x + 0.0125
x = 0.0157
concentration of Co4+ at equilibrium = 0.0157 M