A period 3 element has the following successive ionization energies IE1=1012 IE2=1900 IE3=2910 IE4=4960 IE5=6270 IE6=22200...

A period 3 element has the following successive ionization energies IE1=1012 IE2=1900 IE3=2910 IE4=4960 IE5=6270 IE6=22200 Identify the elements based on these energies

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Expert Solution

clearly... there is a huge step jump in the IE5 vs. IE6 level

meaning that this must have

5 electrons in its valence, and the 6th electron is already in it core configuration

so..

3rd period...

this must be Phosphoprous, which has 5 electrons in its valence shell

so when we take out hte 6th electron, the energy required will be so high as shown in IE6

queen_honey_blossom answered 1 year ago

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