Question

Pick a transition metal and its concentration in seawater and convert it into three different units. I have chosen copper, which is found to be 9.0 x 10^-2 (0.09) ppm in seawater. I need to convert this to three different units, for example, convert ppm to molarity, then molarity to molarity again or convert ppm to g/l. Can you convert this into three different units with the steps to obtain those different units. Thank You.

Answer 1

Answer:

Given that, the concentration of Copper in seawater is 0.09 ppm.

We have to convert this into three different units.

We know that, 1 ppm means 1 g solute present in 10⁶ mL of solvent.

So, 0.09 Copper solution means 0.09 g copper present 10⁶ mL of seawater.

The molar mass of copper is 63.5 g/mol.

Then, 0.09 g Cu = (0.09/63.5) mol = 1.42×10^-3 mol.

A. In molarity:

10⁶ seawater contains 1.42×10^-3 moles of Cu.

Then, 1000 mL of seawater contains 1.42 moles of Cu.

Hence, the molarity is 1.42 mol/L = 1.42 M.

B. In g/L:

Hence, 0.09 ppm solution means 1 L seawater contains 0.09 mg of Cu.

So, 0.09 mg = 0.09×10^-3 g = 9×10^-5 g.

Hence, the required concentration in g/L is 9×10^-5 g/L.

Therefore, the required concentration in molarity is 1.42 M and the also in g/L is 9×10^-5 g/L.

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