In: Chemistry
What is the standard voltage or cell potential of a Cr-Hg cell?
(Remember to switch one-half reaction to oxidation and to balance
the number of electrons--use paper.)
Cr3+(aq)+ 3e- → Cr(s) Eo = -0.74
V
Hg2+(aq)+ 2e- → Hg(l) Eo = +0.789
V
Cr3+(aq)+ 3e- → Cr(s)
Eo = -0.74 V
Hg2+(aq)+ 2e- →
Hg(l)
Eo = +0.789 V
2Cr(s) --------------------> 2Cr^3+ + 6e^- E0 = 0.74v oxidation
3Hg^2+ + 6e^- -------> 3Hg(l) E0 = 0.789v reduction
-----------------------------------------------------------------------------
2Cr(s) + 3Hg^2+(aq) ------------> 2Cr^3+(aq) + Hg(l) E0 cell = 1.529v