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At what pH is the cell potential of the following half-cell +1.20 V? Cr2O7 2- (aq)...

At what pH is the cell potential of the following half-cell +1.20 V?
Cr2O₇ ^2- (aq) + 14H⁺ (aq) + 6e^- → 2Cr₃ + (aq) + 7H₂O (l)
The temperature is 298 K, the pressure is 1 bar and the concentration of Cr2O₇ ^2- (aq) and Cr₃⁺ (aq) is 1 mole dm^-3

Expert Solution

The standard cell potential of the reaction is taken from the standard table,

Now according to nernst equation we have,

Now the half cell potential is given as

Now,

So,

To convert a number from a natural to a common log, use the equation, ln(x) = log(x) ÷ log(2.71828).

Now pH is defined as,

So at a pH of 1.159 the cell potential of the following half-cell is +1.20 V
Cr2O7 2- (aq) + 14H+ (aq) + 6e- → 2Cr3 + (aq) + 7H2O (l)

Amanda K answered 6 months ago

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