Question

In: Chemistry

What is the cell potential of the following cell at 25 oC? Standard Reduction table Cr...

What is the cell potential of the following cell at 25 oC?

Standard Reduction table

Cr / Cr3+ (0.053 M) // Ag1+ (0.52 M) / Ag

E=____________ V

Solutions

Expert Solution

Cr(s) -------------------------> Cr^3+ (aq) + 3e^-             E0 = 0.74v

3Ag^+ (aq) + 3e^- ---------------> 3Ag(s)                        E0 = 0.80v

---------------------------------------------------------------------------------------------

Cr(s) + 3Ag^+ (aq) ------------------> Cr^3+ (aq) + 3Ag(s)   E0 cell = 1.54v

n = 3

[Cr^3+]   = 0.053M

[Ag^+] = 0.52M

Ecell    = E0cell - 0.0592/n logQ

          = 1.54- 0.0592/3 log[Cr^3+]/[Ag^+]^3

        = 1.54 -0.0197log0.053/(0.52)^3

       = 1.54 - 0.0197log0.376

      = 1.54-0.0197*-0.4248

        = 1.548v >>>>>answer


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