Question

sulfur mustard formula is C₄H₈Cl₂S

1. How many moles of sulfur are in 35.6 g of sulfur mustard

2. How many atoms of sulfur are in 1.0 mol of sulfur mustard

3. How many grams of sulfur are in 3.5 x 10²³ molecules of sulfur mustar

Answer 1

1)

Molar mass of C4H8Cl2S,

MM = 4*MM(C) + 8*MM(H) + 2*MM(Cl) + 1*MM(S)

= 4*12.01 + 8*1.008 + 2*35.45 + 1*32.07

= 159.07 g/mol

mass(C4H8Cl2S)= 35.6 g

number of mol of C4H8Cl2S,

n = mass/molar mass

=(35.6 g)/(159.07 g/mol)

= 0.224 mol

1 mol of C4H8Cl2S has 1 mol S

mol of S = mol of C4H8Cl2S = 0.224 mol

Answer: 0.224. mol

2)

1 mol of C4H8Cl2S has 1 mol S

mol of S = mol of C4H8Cl2S = 1.0 mol

number of atoms of S = mol of S * 6.022*10^23 atoms = 1.0 * 6.022*10^23 atoms = 6.022*10^23 atoms

Answer: 6.022*10^23 atoms

3)

mol of sulfur mustar = number of molecules of sulfur mustar / Avogadro’s number

= (3.5*10^23)/(6.022*10^23)

= 0.5812 mol

mass of S = mol of S * molar mass of S

mass of S = 0.5812 mol * 32 g/mol

mass of S = 18.6 g

Answer: 18.6 g