Question

A) how many moles of c are present in 0.719 moles of Benadryl formula C17H21NO
B) how many moles of H are present in 1.65 moles of Benadryl formula c17h21no
C) moles of n are present in 1.56 moles of Benadryl formula C17H21NO

Answer 1

a)

In one mole of C₁₇H₂₁NO contains 17 mol of C (look at the subscript of C in C₁₇H₂₁NO)

So mole ratio = C₁₇H₂₁NO: C = 1:17

Moles of C present in 0.719 moles C₁₇H₂₁NO =

=12.2 mol C

Moles of C present in 0.719 moles of Benadryl = 12.2 mol C

b)

Similarly we can do for H and N

First let us do for N

In one mole of C₁₇H₂₁NO contains 21 mol of H (look at the subscript of H in C₁₇H₂₁NO)

So mole ratio = C₁₇H₂₁NO: C = 1:21

Moles of H present in 1.65 moles C₁₇H₂₁NO =

=34.65 mol H

Moles of H present in 1.65 moles of Benadryl = 34.6 mol H

C)

Similarly we can do for N

In one mole of C₁₇H₂₁NO contains 1 mol of N

So mole ratio = C₁₇H₂₁NO: N = 1:1

Moles of N present in 1.56 moles C₁₇H₂₁NO =

=1.56 mol N

Moles of N present in 1.56 moles of Benadryl = 1.56 mol N