Which are the Brønsted–Lowry acids in the following
equilibrium?Which are the Brønsted–Lowry acids in the following
equilibrium? CH3COOH(aq) + NaOH(l)⇌ NaCH3COO(aq) +
H2O(l)CH3COOH(aq) + NaOH(l)⇌ NaCH3COO(aq) + H2O(l)
Select one:
a. CH3COO–and OH––
b. H2O and OH–
c. H2O, CH3COOH, and OH–
d. CH3COO–and CH3COOH
e. H2O and CH3COOH
Which statement is false?
Ni2+(aq) + 6H2O(l) → [Ni(H2O)6]2+(aq) is a Lewis acid-base
reaction
all Brønsted-Lowry bases are also potential Lewis bases
Ni2+(aq) + CO32–(aq) → NiCO3(s) is a Lewis acid-base
reaction
HNO2 is a Brønsted-Lowry acid but is not a Lewis acid
H+(aq) + H2O(l) → H3O+(aq) is a Lewis acid-base reaction
BF3 + F– → BF4– is a Lewis acid-base reaction
Which statement is false?
Ni2+(aq) + 6H2O(l) → [Ni(H2O)6]2+(aq) is a Lewis acid-base
reaction
all Brønsted-Lowry bases are also potential Lewis bases
Ni2+(aq) + CO32–(aq) → NiCO3(s) is a Lewis acid-base
reaction
HNO2 is a Brønsted-Lowry acid but is not a Lewis acid
H+(aq) + H2O(l) → H3O+(aq) is a Lewis acid-base reaction
BF3 + F– → BF4– is a Lewis acid-base reaction
a) identify the conjugate acid-base pairs for the
following reaction: H2O (aq) + CN- (aq)--->HCN (aq)+OH- (aq) b)
give the conjugate acid of HSO4- and PO4 -2 c) give the
conjugate base of HCLO4 and H3O+
The reaction of the weak acid HCN with the strong base KOH is:
HCN(aq)+KOH(aq)-->HOH(l)+KCN(aq) To compute the pH of the
resulting solution if 54mL of 0.79M HCN is mixed with 2.0 × 10^1 mL
of 0.32 KOH we need to start with the stoichiometry. Let\'s do just
the stoich in steps:. a)How many moles of acid? b)How many moles of
base? c)What is the limiting reactant? d)How many moles of the
excess reagent after reaction? e)What is the concentration of...
Consider the following dissociation of the weak acid, HCN:
HCN(aq) ⇌ CN−(aq) + H+(aq) K = 6.2×10-10 A solution is made with an
initial concentration of 2.60 M HCN. At equilibrium, what is the
concentration of H+ ions in solution? (Hint: You may use the 5%
approximation.)
?M
For the following acid-base reaction H₂S(aq) + CN⁻(aq) ⇌ HS⁻(aq)
+ HCN(aq) ∆H° = -24.7 kJ/mol and ∆S° = -49.9 J/mol・K. If you mix
100 mL of 0.0150 M NaCN with 100 mL of 0.0150 M H₂S, after
equilibrium is established at 25°C what will be the molar
concentration of HCN?