The reaction of the weak acid HCN with the strong base KOH is: HCN(aq)+KOH(aq)-->HOH(l)+KCN(aq) To compute...

The reaction of the weak acid HCN with the strong base KOH is: HCN(aq)+KOH(aq)-->HOH(l)+KCN(aq) To compute the pH of the resulting solution if 54mL of 0.79M HCN is mixed with 2.0 × 10^1 mL of 0.32 KOH we need to start with the stoichiometry. Let\'s do just the stoich in steps:. a)How many moles of acid? b)How many moles of base? c)What is the limiting reactant? d)How many moles of the excess reagent after reaction? e)What is the concentration of the excess reagent after reaction? f)What is the concentration of the pH active product after reaction? ANSWERS a) 42.66* 10^-2 b).0064 c)KOH d)0.03626 e)0.49 f) PLEASE HELP ME FIND THE CONCENTRATION OF THE pH active product after reaction EXPLAIN PLEASE

Expert Solution

queen_honey_blossom answered 2 years ago

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