Question

1. Insomnia has become an epidemic in the United States. Much research has been done in the development of new pharmaceuticals to aide those who suffer from insomnia. Alternatives to the pharmaceuticals are being sought by sufferers. A new relaxation technique has been tested to see if it is effective in treating the disorder. Sixty insomnia sufferers between the ages of 18 to 40 with no underlying health conditions volunteered to participate in a clinical trial. They were randomly assigned to either receive the relaxation treatment or a proven pharmaceutical treatment. Thirty were assigned to each group. The amount of time it took each of them to fall asleep was measured and recorded. The data is shown below. Run an independent samples t-test to determine if the relaxation treatment is more effective than the pharmaceutical treatment at a level of significance of 0.05. Report the test statistic using correct APA formatting and interpret the results.

****PLEASE HELP WALK ME THROUGH SPSS, I HAVE BEEN STUCK ON THIS PROBLEM FOR DAYS! ****

Relaxation	Pharmaceutical
98	20
117	35
51	130
28	83
65	157
107	138
88	49
90	142
105	157
73	39
44	46
53	194
20	94
50	95
92	161
112	154
71	75
96	57
86	34
92	118
75	41
41	145
102	148
24	117
96	177
108	119
102	186
35	22
46	61
74	75

Answer 1

Enter the data into SPSS.

Now, go to Variable View at the bottom next to the Data View option and name the variables.

Also, name the groups by going to Values under Groups option.

Now, let's perform the test. Go to Data View > Analyze > Compare Means > Independent-Samples T Test.

Select the groups.

Go to Define Groups to define the groups.

Click Continue and OK.

The output is:

The hypothesis being tested is:

H₀: µ₁ = µ₂

H₁: µ₁ < µ₂

The test statistic, t = -2.482

The p-value is 0.017/2 = 0.0085.

We divide the p-value by 2 because SPSS always generates the two-tailed value while we need the one-tail value for this problem.

Also, the p-value < 0.05 for the F-test, we would look at the output from Equal variance not assumed column.

Since the p-value (0.0085) is less than the significance level (0.05), we can reject the null hypothesis.

Therefore, we can conclude that the relaxation treatment is more effective than the pharmaceutical treatment.

Please give me a thumbs-up if this helps you out. Thank you!