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A drug tagged with 99U (half-life = 6.05 hr) is prepared for a patient. If the...

A drug tagged with 99U (half-life = 6.05 hr) is prepared for a patient. If the original activity of the sample was 1.51E+4 Bq, what is its activity after it has sat on the shelf for 1.81 hr? Give answer in decays/s. Do not enter units.

Solutions

Expert Solution

final activity = initial activity * e^(-p * time)

p = ln(2) / half-life

p = ln(2) / 6.05

p = 0.114569

final activity = 1.6 * 10^4 * e^-(0.114569 * 1.81)

final activity = 13003.5036

genius_generous answered 2 years ago
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