In: Chemistry
Drug A has the following characteristics: Volume of distribution (Vd) = 40 liters; Half-Life = 15 hours. Assuming a dose of 150 mg given every twenty-four hours and a 70% absorption rate, what is the estimated steady state concentration of the drug?
Kinetics of this drug is first order, because reaches steady state
Calculate elimination rate constant K by using first order kinetics.
K = ln2/t1/2
Half-Life = 15 hours (given)
K = 0.693/15hours = 0.0642/ hours
Calculate clearance CL by using formula
K = CL/Vd
Where Vd = volume of distribution = 40 liters (given)
CL = K x Vd = 0.0642/ hours x 40 liters = 2.568 liters/hour
Now calculate steady state concentration of the drug by using formula
C = F D/CL x t
D = dose = 150 mg (given)
t = dosing interval = 24 hours (given)
CL = clearance = 2.568 liters/hour
F = fraction absorbed = 70/100 = 7/10
Steady state concentration = (7/10 *150 mg) /(2.568 liters/hour x 24 hour) = 1.70 mg/liter
The estimated steady state concentration of the drug is 1.70 mg/liter