Question

dk

Answer 1

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

Consider the rods plus disc system shown in the Figure. The rod has a length L =1.00 m, and mass M = 0.310kg. The large disc has a radius of R = 0.250m and mass m=0.930kg. The second disk should be treated as a point mass of 0.465kg. It is glued to the rod at position X = 0.29 m. The system behaves as a compound pendulum that oscillates about pivot point P. The pivot is at P where the tip of rod rod meets with one end of the disk. Assume that the disc and rod have uniform mass distributions.

a) Find how far below P is the center of mass of the rods and disks system. Answer in units of m.

b) Find the moment of inertia of one of the rod, in units of kgm², as it freely rotates about the pivot point P.

c) Find the moment of inertia of the disk (the large disk), in units of kgm², about its center of mass.

d) Find the moment of inertia of the disk (the large disk), in units of kgm², as it freely rotates about the pivot point P.

e) Find the moment of inertia of the whole system, in units of kgm², as it freely rotates about the pivot point P.