Let

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Expert Solution

Assume molarity of calcium nitrate was x

moles of calcium nitrate = molarity * volume = x *0.05 = 0.05x moles

moles of potasium nitrate = molarity * volume = 0.250 *0.150 = 0.0375 moles

for one mole of calcium nitarate there are two moles of nitrate and for one mole of potasium nitrate there are one mole of nitrate

total moles of nitrate = moles of nitrate from calcium nitrate + moles of nitratate from potasium nitrate

= 2*0.05x + 0.0375 = 0.1 x +0.0375

Total volume after mixing = 50 +150 = 200 mL = 0.2 Litre

molarity nitrate = total moles of nitrate / total volume after mixing = (0.1 x +0.0375) / 0.2

molarity of nitrate is given 0.585

put this in equation

0.585 = (0.1 x +0.0375) / 0.2

0.1 x +0.0375 = 0.117

0.1 x = 0.0795

x = 0.795 M

A) 0.795M is the answer

molarity of Calcium nitrate = 0.795 M

queen_honey_blossom answered 1 year ago

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