Question

In: Chemistry

Suppose a photon excites an electron such that the electron is removed from a bonding orbital...

Suppose a photon excites an electron such that the electron is removed from a bonding orbital and placed in an antibonding orbital. How does the bond order change for this molecule?

Select one:

a. increases by 0.5

b. increases by 1.0

c. decreases by 0.5

d. decreases by 1.0

Expert Solution

The bond order is determined as

Bond order = (Number of electrons in bonding orbital - Number of electrons in antibonding orbital ) / 2

So let say the number of electrons in bonding orbital = 10 (initially) and in ABMO =5

Bond order = 10-5/2 = 2.5

After exitation, number of electrons in bonding orbital = 9 and in ABMO = 6

Bond order = 9-6/2 = 1.5 , so it decreased by 1.

Hence answer is decreased by 1.0

In general ,

Let electrons in bonding orbital = b

Electron in antibonding orbtial = a

After exitation , b-1 and a+1

Let, a-b/2 = c (bond order)

After exitation

(a-1)-(b+1) /2 = a-b -2 /2 = a-b/2 - 1 = c-1 (decreased by 1)

queen_honey_blossom answered 2 years ago

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