Question

a sample of krypton gas occupies 95.0 mL at .500 atm. If the temperature remained constant what volume the krypton occupy at 5.00 atm, .05000 atm, 555 torr, 5.00 torr and 5X5 10 to the negative 2 torr

Answer 1

Ans :- a) For 5atm

Given P₁ =0.5atm

V₁ =95ml

P₂ =5atm

From boyle's law

when temperature is constant we have

P₁V₁ =P₂V₂

0.5 x 95 =5xV₂

V₂ = 9.5ml

Therefore at 5atm krypton occupy 9.5ml

b) For 0.05atm

P₁=0.5atm

P₂=0.05 atm

V₁ = 95ml

V₂ =

We know P₁V₁ =P₂V₂

0.5x95=0.05xV₂

V₂ = 950ml

Therefore at 0.05atm krypton occupies 950ml

c) For 555 torr

P₁ =0.5atm

P₂ =555 torr

Now 1 torr=0.00131579atm

555 torr = 0.73atm

Therefore P₂ =0.73atm

V₁=95ml

We know

P₁V₁ =P₂V₂

0.5x95=0.73xV₂

V₂ = 65.06ml

therefore at 555 torr krypton occupies 65.06ml

d) For 5 torr

P₁=0.5atm

P₂ = 5torr

Now 1torr =0.0013157atm

5 torr = 0.0065atm

Therefore P₂ =0.0065atm

V₁=95ml

V₂ =?

P₁V₁=P₂V₂

0.5x95=0.0065xV₂

V₂ = 7307.6ml

Therefore at 5torr krypton gas occupies 7307.6ml