2KMnO4+16HCl -> 5Cl2+2KCl+2MnCl2+8H20 a. How many moles of HCl are required to react 25.0g of KMn04?...

2KMnO4+16HCl -> 5Cl2+2KCl+2MnCl2+8H20

a. How many moles of HCl are required to react 25.0g of KMn04?

b. How many Cl2 molecules will be produced using 5.0 moles KMnO4?

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Expert Solution

queen_honey_blossom answered 1 year ago

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