Cystic fibrosis is caused by a recessive allele. (Use "N" to stand for the normal, non-disease...

Cystic fibrosis is caused by a recessive allele. (Use "N" to stand for the normal, non-disease allele). If parents that are both heterozygous for cystic fibrosis have a child, what is the percent chance that the child will have the disease?

Expert Solution

Answer-

According to the given question-

Cystic fibrosis is due to the presence of recessive allele i.e. nn. When we make a cross between two parents that are heterozygous for cystic fibrosis i.e. Nn then their children will be-

Nn Nn

	N	n
N	NN (Normal)	Nn (Carrier, no Cystic fibrosis )
n	Nn (Carrier, no Cystic fibrosis )	nn (with Cystic fibrosis )

When we make a cross between parents which are heterozygous for Cystic fibrosis then there are 3 out of 4 children are normal which means that the chances of getting a normal child are 75 % and out of 3 children which are normal, 1 child in normal but 2 children are carriers for cystic fibrosis but 1 out of 4 children will be with cystic fibrosis which means that the chances of getting a child with cystic fibrosis are 25 %.

So if the heterozygous parents have a child then there are 75 % chances that the child will be normal and 25 % chances the child will be with cystic fibrosis.

gladiator answered 1 year ago

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