Cystic fibrosis is caused by a mutation in a single gene. Homozygotes for this mutant recessive...

Cystic fibrosis is caused by a mutation in a single gene. Homozygotes for this mutant recessive allele (ff) have cystic fibrosis. Within a population, 2% of people have cystic fibrosis. Assuming Hardy-Weinberg equilibrium, the frequency of heterozygotes in the population is 0.24.

If inbreeding was common in this population, what would happen to the percentage of people who have cystic fibrosis over time?

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Expert Solution

This question based on hardy Weinberg equilibrium principle

Inbreeding is the mating of two closely relatives and producing offspring which causes change in genotype proportion of population

As given in the question that if Inbreeding is common in population than the population will not be in hardy Weinberg equilibrium as genotype proportion of population will not remain constant

As inbreeders are closed relative they have common alleles so when mating occurs between them there is more chance that offspring will be homozygous than heterozygous hence there will be increase in percentage of homozygous and decrease in percentage of heterozygous

Plz upvote my answer Thank you?

gladiator answered 1 year ago

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