In: Advanced Math
if order of a= order of b in a finite Abelian group , is order of ab= order of a?
If you have any doubts in the solution please ask me in comments...
Given claim is not true if you take abelian group {1,-1,i,-i}
Here we have
order of (i)= order of (-i) =4
But order of (-i×i=1) is =1 which is not equal to 4